loop issues

[Vegas/Newbie]

I am working on a simple for/while loop in class which requires the loop to end after 10 entries. I am having trouble engaging the count to stop the loop. Where am I going wrong? Any suggestions? Thanks in advance...

#include <iostream>
#include <string>
#pragma hdrstop

int main()
{
string lastname;
float count, rate, num, sales, pay;
count = 1;
do
{
rate = 300;
count = 0;
cout << "Enter employee last name: ";
cin >> lastname;
cout << "Enter employee number: ";
cin >> num;
cout << "Enter employee weekly sales: ";
cin >> sales;

if (sales <= 500)
{
pay = rate + (0.1 * sales);
cout << "Employee: "<< lastname << ", Number: "<< num << ", Made $" << pay << " \n";
cout << count << endl;
}
else
{
if (sales > 500)
{
pay = ((sales - 500) * 0.15) + 350;
cout << "Employee: "<< lastname << ", Number: "<< num << ", Made $" << pay << " \n";
cout << count << endl;
}
}
}
while (count <= 10);
{count ++;}
cin.get();
cin.get();
return 0;
}

[EscapeCharacter]

everytime your loop runs count is being set to zero, and even if you were incrementing in the loop(which you arent) it would still equal zero everytime it loops

[Vegas/Newbie]

everytime your loop runs count is being set to zero, and even if you were incrementing in the loop(which you arent) it would still equal zero everytime it loops

My original question was where was I going wrong? I realize that the counter is not working. I am unsure of how the program has to be manipulated so that the counter does work...
Thanks

[AdaHacker]

Um, maybe increment count instead of setting it to zero? If you set count to zero at the beginning of every iteration and never increase it, then it will obviously never be greater than 10. In fact, it will never even be anything other than zero.

[Vegas/Newbie]

Thanks alot. Duh! Basic math rules. I feel much dumber after posting that code now. But I have another if thou art interested. hehe.

Riddle me this:

A loop that sums the odd numbers between 1 and 100. I can get them to increment in odd numbers, but cannot get the sum of them. I will probably feel stupid posting this one too, but we all started somewhere right?

#include <iostream.h>
#pragma hdrstop

int main()
{
int x, sum;
x = 1;

do
{
cout << x << endl;
x = x + 2;
sum = ?? /* Here is the problem. Do I need
another variable to make this work? */

}
while (x < 100);
cin.get();
cin.get();
return 0;
}

[sharth]

set sum = to 0 outside the loop.

sum += x as your sum = ?
and do the sum += x before the x += 2

[Vegas/Newbie]

I tried your suggestion sharth, and I still get incrementing values with no sum (total to be exact).

Can I make an equation to output the sum of all odd numbers between 1 and 100 with only 2 variables?

[sharth]

#include <iostream.h>

int main() {
int x=1, sum=0;
do {
cout << x << endl;
sum += x;
x += 2; // increases x to next odd number.
} while (x <= 100);

cout << "\n\nSum: " << sum;
cout << endl;
return(0);
}

[sharth]

what happened, was that you simply forgot to output what sum equaled at the end of the code.

[Vegas/Newbie]

sharth, thanks for the much appreciated help.

Being new to C++, it is rather frustrating at times.

I enjoy absorbing as much as possible. It helps to know that these forums offer much insight for those like myself who aren't as efficient programmers as others.

Just one silly question though:
what, in lamens terms, does += stand for? Is it the same as saying blah = blah + yada? I see it as being plus equal to. Is that right, like <= is less than or equal to?

Thanks,
A sponge :)

[sharth]

x += y is the same as x = x + y :)