siqe
11-26-2000, 05:49 PM
void find_hi_lo(double averages[], double *lowest_average, double *highest_average)
{
*highest_average = 0;
*lowest_average = 200;
int x;
{
*highest_average = 0;
*lowest_average = 200;
int x;
|
Click to See Complete Forum and Search --> : WHERE IS THE "PARSE ERROR" IN THESE 6 LINES siqe 11-26-2000, 05:49 PM void find_hi_lo(double averages[], double *lowest_average, double *highest_average) { *highest_average = 0; *lowest_average = 200; int x; siqe 11-26-2000, 05:55 PM gcc says its before int x; siqe 11-26-2000, 05:59 PM what the hell is this, i put the int x; before all the pointer crap and it works? why is that. Mikenell 11-26-2000, 06:27 PM Whats the exact error gcc gives? Mikenell Death on Wheels 11-26-2000, 06:33 PM It looks like you left out the closing brace to close out the function, for starters. ------------------ Kurt Weber Shell scripts? Shell scripts? We don't NEED no stinkin' shell scripts! White, heterosexual, middle-class, and proud! I've never understood why Bill Gates would name his company after his penis. kervin 11-26-2000, 07:15 PM I might be wrong, but try initializing x first then change the other variables. C variables have to be declared before any other code. void find_hi_lo(double averages[], double *lowest_average, double *highest_average) { int x; *highest_average = 0; *lowest_average = 200; kervin 11-26-2000, 07:26 PM Plus, why are you derefencing the pointers before changing them? You only should do that if you have 2 levels of indirection eg. (forgive me, I don't have a compiler, but something like this should work) double **a; /* a is a pointer to a pointer */ double c = 0.5 double *b = c; /* b points to c */ a = &b; *a = 3.0 now the value in c should be 3.0 not 0.5 dunno 11-26-2000, 07:53 PM In C you need to declare ALL variables at the beginning of a function, group of statements, etc. ------------------ "I'll get enough sleep when I'm dead." --Left Behind, The Movie justlinux.com
Copyright Internet.com Inc. All Rights Reserved. |